💡 2nd Grade Math: 3-Digit Addition and Subtraction Practice Questions

To add 3-digit numbers, we add the digits in each place value column, starting from the ones place.

• 👉 Step 1: Add the Ones Place
  We add the ones digits: \( 5 + 3 = 8 \).
• 👉 Step 2: Add the Tens Place
  Next, we add the tens digits: \( 4 + 2 = 6 \).
• 👉 Step 3: Add the Hundreds Place
  Finally, we add the hundreds digits: \( 3 + 1 = 4 \).

✅ So, when we put it all together, we get:

The sum is 468.

To subtract 3-digit numbers, we subtract the digits in each place value column, starting from the ones place.

• 👉 Step 1: Subtract the Ones Place
  We subtract the ones digits: \( 8 - 5 = 3 \).
• 👉 Step 2: Subtract the Tens Place
  Next, we subtract the tens digits: \( 6 - 3 = 3 \).
• 👉 Step 3: Subtract the Hundreds Place
  Finally, we subtract the hundreds digits: \( 7 - 2 = 5 \).

✅ So, when we put it all together, we get:

The difference is 533.

We'll add the numbers by place value, remembering to regroup when a sum is 10 or more.

• 👉 Step 1: Add the Ones Place
  Add the ones digits: \( 7 + 6 = 13 \). Since 13 is 1 ten and 3 ones, we write down 3 in the ones place and carry over 1 to the tens place.
• 👉 Step 2: Add the Tens Place
  Add the tens digits, including the carried-over ten: \( 2 + 3 + 1 \text{ (carried over)} = 6 \). We write down 6 in the tens place.
• 👉 Step 3: Add the Hundreds Place
  Add the hundreds digits: \( 4 + 1 = 5 \). We write down 5 in the hundreds place.

✅ So, the sum is:

The sum is 563.

We'll subtract the numbers by place value, remembering to regroup (borrow) when a digit is too small.

• 👉 Step 1: Subtract the Ones Place
  We need to subtract \( 2 - 9 \). Since 2 is smaller than 9, we need to regroup. We take 1 ten from the tens place (5 tens becomes 4 tens) and add it to the ones place (2 ones becomes 12 ones). Now we have \( 12 - 9 = 3 \). We write down 3 in the ones place.
• 👉 Step 2: Subtract the Tens Place
  Now we subtract the tens digits. Remember, we used one ten, so we have 4 tens left: \( 4 - 1 = 3 \). We write down 3 in the tens place.
• 👉 Step 3: Subtract the Hundreds Place
  Subtract the hundreds digits: \( 6 - 2 = 4 \). We write down 4 in the hundreds place.

✅ So, the difference is:

The difference is 433.

To find out how many cars Mia and Leo have altogether, we need to add Mia's red cars, Mia's blue cars, and Leo's green cars.

• 👉 Step 1: Find Mia's total cars first (optional, but good for breaking down the problem)
  Mia's red cars + Mia's blue cars: \( 215 + 148 \)
\[ \begin{array}{r} \text{ }^1 \\ 215 \\ +148 \\ 363 \end{array} \]

Mia has 363 cars.

• 👉 Step 2: Add Mia's cars to Leo's cars
  Mia's total cars + Leo's green cars: \( 363 + 105 \)
\[ \begin{array}{r} 363 \\ +105 \\ 468 \end{array} \]

✅ Mia and Leo have 468 cars altogether.

To find out "how many more" or the "difference," we need to subtract the smaller number from the larger number.

• 👉 Step 1: Set up the subtraction problem
  We need to calculate \( 380 - 250 \).
• 👉 Step 2: Subtract the Ones Place
  \( 0 - 0 = 0 \).
• 👉 Step 3: Subtract the Tens Place
  \( 8 - 5 = 3 \).
• 👉 Step 4: Subtract the Hundreds Place
  \( 3 - 2 = 1 \).

✅ So, the calculation is:

The farmer planted 130 more apple trees than pear trees.

To find out how many pages Sarah has read so far, we need to add the pages she read on Monday and Tuesday.

• 👉 Step 1: Add the pages read on Monday and Tuesday
  We need to calculate \( 118 + 105 \).
• 👉 Step 2: Add the Ones Place
  \( 8 + 5 = 13 \). Write down 3 and carry over 1 to the tens place.
• 👉 Step 3: Add the Tens Place
  \( 1 + 0 + 1 \text{ (carried over)} = 2 \). Write down 2 in the tens place.
• 👉 Step 4: Add the Hundreds Place
  \( 1 + 1 = 2 \). Write down 2 in the hundreds place.

✅ So, the sum is:

Sarah has read 223 pages so far.

To find out how many toy robots were sold, we need to subtract the number of robots left from the number of robots they started with.

• 👉 Step 1: Set up the subtraction problem
  We need to calculate \( 450 - 125 \).
• 👉 Step 2: Subtract the Ones Place
  We need to subtract \( 0 - 5 \). We can't do that, so we regroup. Take 1 ten from the tens place (5 tens becomes 4 tens) and add it to the ones place (0 ones becomes 10 ones). Now we have \( 10 - 5 = 5 \).
• 👉 Step 3: Subtract the Tens Place
  Now we subtract the tens digits. Remember, we used one ten, so we have 4 tens left: \( 4 - 2 = 2 \).
• 👉 Step 4: Subtract the Hundreds Place
  Subtract the hundreds digits: \( 4 - 1 = 3 \).

✅ So, the calculation is:

The toy store sold 325 toy robots today.